Optimal. Leaf size=78 \[ \frac{\cos (e+f x) (3-5 \sin (e+f x))^{-m} (5 \sin (e+f x)-3)^m \, _2F_1\left (\frac{1}{2},m+1;\frac{3}{2};\frac{4 (1-\sin (e+f x))}{\sin (e+f x)+1}\right )}{f (\sin (e+f x)+1)} \]
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Rubi [A] time = 0.0933549, antiderivative size = 111, normalized size of antiderivative = 1.42, number of steps used = 2, number of rules used = 2, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.074, Rules used = {2788, 132} \[ \frac{\sqrt{\frac{1-\sin (e+f x)}{\sin (e+f x)+1}} \cos (e+f x) (3-5 \sin (e+f x))^{-m} (\sin (e+f x)+1)^m \, _2F_1\left (\frac{1}{2},-m;1-m;-\frac{3-5 \sin (e+f x)}{\sin (e+f x)+1}\right )}{4 f m (1-\sin (e+f x))} \]
Antiderivative was successfully verified.
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Rule 2788
Rule 132
Rubi steps
\begin{align*} \int (3-5 \sin (e+f x))^{-1-m} (1+\sin (e+f x))^m \, dx &=\frac{\cos (e+f x) \operatorname{Subst}\left (\int \frac{(3-5 x)^{-1-m} (1+x)^{-\frac{1}{2}+m}}{\sqrt{1-x}} \, dx,x,\sin (e+f x)\right )}{f \sqrt{1-\sin (e+f x)} \sqrt{1+\sin (e+f x)}}\\ &=\frac{\cos (e+f x) \, _2F_1\left (\frac{1}{2},-m;1-m;-\frac{3-5 \sin (e+f x)}{1+\sin (e+f x)}\right ) (3-5 \sin (e+f x))^{-m} \sqrt{\frac{1-\sin (e+f x)}{1+\sin (e+f x)}} (1+\sin (e+f x))^m}{4 f m (1-\sin (e+f x))}\\ \end{align*}
Mathematica [C] time = 1.76284, size = 246, normalized size = 3.15 \[ -\frac{2^{2 m-1} (\cosh (m \log (4))-\sinh (m \log (4))) (3-5 \sin (e+f x))^{-m} (\sin (e+f x)+1)^m (\sin (e+f x)+i \cos (e+f x)+1) \left (\frac{2 \sin \left (\frac{1}{4} (2 e+2 f x-\pi )\right )-\cos \left (\frac{1}{4} (2 e+2 f x-\pi )\right )}{2 \sin \left (\frac{1}{4} (2 e+2 f x-\pi )\right )+\cos \left (\frac{1}{4} (2 e+2 f x-\pi )\right )}\right )^m \, _2F_1\left (m+1,2 m+1;2 (m+1);\frac{2 \cos \left (\frac{1}{4} (2 e+2 f x-\pi )\right )}{\cos \left (\frac{1}{4} (2 e+2 f x-\pi )\right )+2 \sin \left (\frac{1}{4} (2 e+2 f x-\pi )\right )}\right )}{f (2 m+1) ((1+2 i) \sin (e+f x)+(-2+i) \cos (e+f x)+(1-2 i))} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.243, size = 0, normalized size = 0. \begin{align*} \int \left ( 3-5\,\sin \left ( fx+e \right ) \right ) ^{-1-m} \left ( 1+\sin \left ( fx+e \right ) \right ) ^{m}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (\sin \left (f x + e\right ) + 1\right )}^{m}{\left (-5 \, \sin \left (f x + e\right ) + 3\right )}^{-m - 1}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (\sin \left (f x + e\right ) + 1\right )}^{m}{\left (-5 \, \sin \left (f x + e\right ) + 3\right )}^{-m - 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (\sin \left (f x + e\right ) + 1\right )}^{m}{\left (-5 \, \sin \left (f x + e\right ) + 3\right )}^{-m - 1}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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